I have a script that duplicates a Word doc template and renames each using a csv file with a list of names. What would be the equivalent code if instead of a csv file I use a text file?
Import-csv ‘.\individuals2.csv’ | foreach-object {
$newname = ‘2 ‘ + $_.name + '.docx’
Copy-item '.\template.docx' $newname
}
A csv file is a text file. Where the data in text form is in a specific form.
So your question doesn’t really make sense. You’re already using a text file, and you don’t disclose what would be different.
What’s the format of the text file?
His example doesn’t seem to perform any comparisons to determine what to name the file. If the text file is just a list then something like this could work:
$file = Get-Content -Path .\individuals2.txt
foreach ($line in $file) { Copy-Item -Path .\template.docx -Destination “.$(2 + $line + ‘.docs’)” }
Edit: Wow, Lemmy destroys formatting.
It’s markdown, you should be able to indent your lines by 4 spaces or fence with triple backtics to get code blocks. Your client’s editor may have a button to help
``` $file = Get-Content -Path .\individuals2.txt foreach ($line in $file) { Copy-Item -Path .\template.docx -Destination ".\$(2 + $line + '.docs')" } ```Becomes
$file = Get-Content -Path .\individuals2.txt foreach ($line in $file) { Copy-Item -Path .\template.docx -Destination ".\$(2 + $line + '.docs')" }
It’s just a Notepad text file.
The confusion is that CSV is also just a Notepad text file that uses Commas to Separate Values.
They are asking about what kind of values are in it.
